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How Much Pure Acid Should Be Mixed With

How Much Pure Acid Should Be Mixed With. That is an 100% solution).60*5gal + 1.00*x =.80 (5gal + x) solve for x. 8) ) how much pure acid should be mixed with 6 gallons of a 50% acid solution in order to get an 80% acid solution?

Solve problem. See EXAMPLE.Acid Mixture How much pure acid should be
Solve problem. See EXAMPLE.Acid Mixture How much pure acid should be from www.homeworklib.com

X = 5 gal of pure acid needs to be added. Similarly acid content (in ltrs.) from 2nd. Thus, you have 2 solutions:

How Much Pure Acid Should Be Mixed With 5 Gallons Of A 40% Acid Solution In Order To Get A 50% Acid Solution?


Answer by mananth (16092) ( show source ): 8) ) how much pure acid should be mixed with 6 gallons of a 50% acid solution in order to get an 80% acid solution? 0.50*5 + 1* x = 0.80* (5+x).

X = 5 Gal Of Pure Acid Needs To Be Added.


You want to mix these to obtain a solution that is 80% acid. How much pure acid should be mixed with 8 gallons of a 50% acid solution in order to get an 80% acid solution? Pure acid can be considered to be 100% acid.

48Gal +.6Gal = 48.6Gal =.9*54Gal = 48.6Gal.


Complete the table below, let x represent the. Similarly acid content (in ltrs.) from 2nd. Firstly, total solution we will be getting = 12 + 8 = 20 litres.

Now, If We Want A 90%.


0.50*5 + 1* x = 0.80* (5+x) simplify and solve. How much pure acid should be mixed with 6 gallons of 60% acid solution in order to get 70% acid solution? You can put this solution on your website!

Now Acid Content (In Ltrs.) From 1St Solution = 40 % Of 12 Lt.


How much pure acid should be mixed with 3 gallons of a 20% acid solution in order to get a 60% acid solution. Well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water. So, how much acid is there in 6 gallons?

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